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VB6 Download image and automatically center in Picture1 control

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Download the image and automatically center it in the Picture1 control
'References to:
'
' Microsoft Windows Image Acquisition Library v2.0
' Microsoft WinHTTP Services, version 5.1

Code:

Function ShowWebIMG_WIA(imgURL As String, Picture1 As PictureBox)
    Dim Vector As WIA.Vector
   
    Picture1.BorderStyle = 0
    Picture1.ScaleMode = 3 'pix
    Picture1.AutoRedraw = True
   
    With New WinHttp.WinHttpRequest
        .Open "GET", imgURL, Async:=True
        .Send
        .WaitForResponse
        Set Vector = New WIA.Vector
        Vector.BinaryData = .ResponseBody
    End With
    With Vector.ImageFile
          Dim ip As WIA.ImageProcess
          Set ip = CreateObject("WIA.ImageProcess")
            ip.Filters.Add ip.FilterInfos("Scale").FilterID
            ip.Filters(1).Properties("MaximumWidth") = Picture1.ScaleWidth
            ip.Filters(1).Properties("MaximumHeight") = Picture1.ScaleHeight
            Dim IMG2 As WIA.ImageFile
            Set IMG2 = CreateObject("WIA.ImageFile")
            Set IMG2 = ip.Apply(Vector.ImageFile)
            Vector.BinaryData = IMG2.FileData.BinaryData
    End With
    Dim MemPicture As IPictureDisp
    Set MemPicture = Vector.Picture
    With MemPicture
    '.Render Picture1.hDC, (Picture1.ScaleWidth - IMG2.Width) / 2, (Picture1.ScaleHeight - IMG2.Height) / 2, IMG2.Width, IMG2.Height, 0, 0, .Width, .Height, 0        'GOOD1
    .Render Picture1.hDC, (Picture1.ScaleWidth - IMG2.Width) / 2, IMG2.Height + (Picture1.ScaleHeight - IMG2.Height) / 2, IMG2.Width, -IMG2.Height, 0, 0, .Width, .Height, 0      'GOOD1
    End With
    Picture1.Refresh
End Function

Private Sub Command1_Click()
ShowWebIMG_WIA "https://mbdp01.bdstatic.com/static/landing-pc/img/logo_top.79fdb8c2.png", Me.Picture1
End Sub


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